Question:x + y = 2 হলে, দেখাও যে, `x^3 + y^3 + 6xy = 8` 

Answer দেওয়া আছে, x + y = 2 বামপক্ষ `= x^3 + y^3 + 6xy` `= (x + y)^3 - 3xy (x + y) + 6xy` `= (2)^3 - 3xy. 2 + 6xy` [মান বসিয়ে] `= 8 - 6xy + 6xy` = 8 = ডানপক্ষ `:. x^3 + y^3 + 6xy = 8` 

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x + y = 2 hole, dekhao je, `x^3 + y^3 + 6xy = 8`
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