1. Question:Find the radios of a circle of area 38.5 `cm^2` (`pi =22/7` ). 

    Answer
    `pi r^2` = 38.5
    
    `:. r^2` = `38.5/pi` 
    
             = `(38.5 xx 7)/22`
    
             = `(3.5 xx 7)/2`
    
             = `(3.5)^2` .
    
       `:.`r = 3.5
    
    The radius of the circle is 3.5 cm

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  2. Question:Find the area between two circles of radii 4 cm and 3 cm . given that the smaller circle lies entirely within the larger. 

    Answer
    Area of the bigger circle =`pi(4)^2 cm^2` =16`pi cm^2`.
    
    Area of the smaller circle=`pi(3)^2``cm^2`= 9`pi cm^2` .
    
    Area between the circle = (16`pi`- 9`pi`) `cm^2`= 7`pi cm^2`.
    
                                          = 7`xx 22/7 cm^2`
    
                                          = 22 `cm^2`

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  3. Question:Find the volume and total surface area of a right circular cylinder , the radius of whose base is 4 cm and whose height is 5 cm ( Take `pi` to be 3.142) . 

    Answer
    The volume =`pi r^2`h=`pi(4)^2 5 cm^3`
    
                       = 80`pi cm^3`.
    
                       = 251.36 `cm^3`
    
                       = 251 `cm^3`
    
     The area of the curved  surface = 2`pi`rh
    
                                     = 2`pi`(4)(5) `cm^2`  
    
                                     = 40`pi cm^2`.
    
    The area of each end = `pir^2`=`pi(4)^2 cm^2` = 16`pi cm^2`.
    
    The total surface area =(40`pi`+32`pi`) `cm^2`
    
                                       = 72`pi cm^2`
    
                                       =226.224 `cm^2`
    
                                       226 `cm^2`

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  4. Question:Find the volume of material in pipe of length 7 cm, if the internal and external radii are 3 cm and 4 cm (Take `pi` to be `22/7`). 

    Answer
    The volume of the larger cylinder
    
                       = `pi(4)^2` 7 c`m^3`= `pi xx16 xx 7 cm^3`= 112`pi cm^3`.
    
    The volume of the smaller cylinder
    
                       = `pi(3)^2` 7 c`m^3`= 63`pi cm^3`
    
    The volume of the material
                       = (`112 pi - 63 pi` ) `cm^3`
    
                       = 49`pi cm^3`
    
                       = 49`xx 22/7 cm^3`.
    
                       = 154 `cm^3`.

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  5. Question:Evaluate 7`xx`19.3+8`xx`19.3-5`xx`19.3 

    Answer
    7`xx`19.3+8 `xx` 19.3 - 5`xx`19.3
     =19.3(7+8-5)
     =19.3 `xx`10
     =193

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  6. Question:Evaluate 19.3`pi` - 15.8`pi` 

    Answer
    19.3`pi` - 15.8`pi` =`pi`(19.3-15.8)=`pi` `xx`3.5 
    
                                       = `22/7 xx 7/2`
    
                                       = 11

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  7. Question:Factories ax+bx+ay+by 

    Answer
    ax+bx+ay+by = (ax+bx) + (ay+by)
                           = x(a+b) +y (a+b)
                           =(a+b) (x+y).

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  8. Question:Factorise ax + ay -x -y . 

    Answer
    ax + ay -x -y=a(x+y) - (x+y) 
                        =(x+y) (a-1).
    
     Notice that when the last two terms are grouped with a minus sign outside. the signs of both terms in the bracket must be changed.
    
                        ax + ay -x -y=a(x+y) - (x+y) 
     and not     
                       a(x+y) - (x-y) .
    
    It is good plan to remove the brackets mentally to check your working.

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  9. Question:Factorise `xx^2`y - `xxy^2`+3y -3`xx` 

    Answer
    `xx^2`y - `xxy^2`+(3y -3`xx`) = xy(x-y) +3(y-x)
    
    This has no obvious factor as the expression inside the brackets are different .
      but if we arrange the expression as 
       
    `xx^2`y - `xxy^2`-3`xx`+3y) = `xx`y(x-y) -3(x-y),
    
    An obvious factor is now apparent.
    The factors are (x-y)(xy-3).

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  10. Question:Factorise `xx^2`+9x+20. 

    Answer
    `xx^2`+9x+20
    
    =`xx^2`+5x +4x +20
    
    =x(x+5)+(x+4)
    
    =(x+5)  (x+4)

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