what will be output when you execute following c code include stdio..., Data types and variables, Adv C

Question:What will be output when you will execute following c code?#include<stdio.h>
int main(){
    int a= sizeof(signed) +sizeof(unsigned);
    int b=sizeof(const)+sizeof(volatile);
    printf("%d",a+++b);
    return 0;
}

A 10 
B 9 
C 8 
D Error: Cannot find size of modifiers 
E Error: Undefined operator +++

/69

+ AnswerC

+ ExplanationTurbo C++ 3.0: 8
Turbo C ++4.5: 8
Linux GCC: 16
Visual C++: 16

Default data type of signed, unsigned, const and volatile is int. In turbo c 3.0 size of int is two byte.
So, a = 4 and b =4
Now, a+++b
= a++ + b
= 4 + 4  //due to post increment operator.
=8
Note: In turbo c 4.5 and Linux gcc compiler size of int is 4 byte so your out will be 16

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Question:What will be output when you will execute following c code?#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }

A 10

B 9

C 8

D Error: Cannot find size of modifiers

E Error: Undefined operator +++

C

Question:What will be output when you will execute following c code?
#include<stdio.h> int main(){ int a= sizeof(signed) +sizeof(unsigned); int b=sizeof(const)+sizeof(volatile); printf("%d",a+++b); return 0; }