what will be output when you execute following c code define true..., Control Structure, Adv C

Question:What will be output when you will execute following c code?#define True 5==5
#include<stdio.h>
void main(){
    if(.001-0.1f)
         printf("David Beckham");
    else if(True)
         printf("Ronaldinho");
    else
        printf("Cristiano Ronaldo");
}

A David Beckham 
B Ronaldinho 
C Cristiano Ronaldo 
D Warning: Condition is always true 
E Warning: Unreachable code

/69

+ AnswerA D E

+ ExplanationAs we know in c zero represents false and any non-zero number represents true. So in the above code:

(0.001 – 0.1f) is not zero so it represents true. So only if clause will execute and it will print: David Beckham on console.
But it is bad programming practice to write constant as a condition in if clause. Hence compiler will show a warning message: Condition is always true

Since condition is always true, so else clause will never execute. Program control cannot reach at else part. So compiler will show another warning message:
Unreachable code

+ Report

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Question:What will be output when you will execute following c code?#define True 5==5 #include<stdio.h> void main(){ if(.001-0.1f) printf("David Beckham"); else if(True) printf("Ronaldinho"); else printf("Cristiano Ronaldo"); }

A David Beckham

B Ronaldinho

C Cristiano Ronaldo

D Warning: Condition is always true

E Warning: Unreachable code

A D E

Question:What will be output when you will execute following c code?
#define True 5==5 #include<stdio.h> void main(){ if(.001-0.1f) printf("David Beckham"); else if(True) printf("Ronaldinho"); else printf("Cristiano Ronaldo"); }