what will be output when you execute following c code include stdio..., Data types and variables, Adv C

Question:What will be output when you will execute following c code?#include<stdio.h>
int main(){
    signed x,a;
    unsigned y,b;
    a=(signed)10u;
    b=(unsigned)-10;
    y = (signed)10u + (unsigned)-10;
    x = y;
    printf("%d  %u\t",a,b);
    if(x==y)
         printf("%d %d",x,y);
    else if(x!=y)
         printf("%u  %u",x,y);
    return 0;
}
Choose all that apply:

A 10 -10   0 0 
B 10 -10   65516 -10 
C 10 -10   10 -10 
D 10 65526      0 0 
E Compilation error

/69

+ AnswerD

+ ExplanationTurbo C++ 3.0: 10 65526 0 0
Turbo C ++4.5: 10 65526 0 0
Linux GCC: 10 4294967286 0 0
Visual C++: 10 4294967286 0 0

a=(signed)10u;
signed value of 10u is +10
so, a=10
 b=(unsigned)-10;
unsigned value of -10 is :
MAX_VALUE_OF_UNSIGNED_INT – 10 + 1
In turbo c 3.0 compiler max value of unsigned int is 65535
So, b = 65526
y = (signed)10u + (unsigned)-10;
   = 10 + 65526 = 65536 = 0 (Since 65536 is beyond the range of unsigned int. zero is its corresponding cyclic vlaue)
   X = y = 0

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