`(1/6)^(12) xx (8)^(25) xx (3/4)^(15)` `= 1/(2^(12) xx 3^(12)) xx (2^3)^(25) xx 3^(15)/(2^15 xx 2^15)` `= (2^75 xx 3^15)/(2^42 xx 3^12)` `= 2^33 xx 3^3` :. Total number of prime factors `= (33 + 3) = 36`