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Note: On diving, we get` (1 - x^8)/(1 - x^4) ` `= 65/64` `or ((1 - x^4) (1 + x^4))/((1 - x^4))` `= 65/64 or 1 + x^4` `= 65/64` `:. x^4 = (65/64 - 1)` `= 1/64 or x = (1/2^6)^(1/4)` `= + 1/(2^(3/2))` - `= + 1/(2sqrt(2))` -

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Note: Given equations are : `2^a + 3^b = 17, 2^2 - 3. 3^b = 5` `or x + y = 17 & 4x - 3y = 5,` where `x = 2^a & y = 3^b.` On solving, we get : x = 8 and y = 9. `:. 2^a = 8 = 2^3` and` 3^b = 9 = 3^2` :. a = 3 and b = 2

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