Question:When running the following SELECT query:SELECT ID FROM (
SELECT ID, name FROM (
SELECT *
FROM employee
)
);
The error message 'Every derived table must have its own alias' appears.
Which of the following is the best solution for this error?
A SELECT ID FROM ( SELECT ID AS SECOND_ID, name FROM ( SELECT * FROM employee ) );
B SELECT ID FROM ( SELECT ID, name AS NAME FROM ( SELECT * FROM employee ) );
C SELECT ID FROM ( SELECT ID, name FROM ( SELECT * FROM employee ) AS T ) AS T;
D SELECT ID AS FIRST_ID FROM ( SELECT ID, name FROM ( SELECT * FROM employee ) );