+ Explanationsolution:
`(A + B)`'s 1 day's work = `1/5`;
`(B + C)`'s 1 day's work = `1/7` and
`(A + C)`'s 1 day's work = `1/4`.
`2(A + B + C)`'s 1 day's work =`(1/5 + 1/7 + 1/4)`
=`83/140`.
`(A + B + C)`'s 1 day's work = `83/280`.
C's 1 day's work =`(83/280 - 1/5)`
= `27/280`.
A's 1 day's work =`(83/280 - 1/7)`
=`43/280`.
B's 1 day's work =`(83/280 - 1/4)`
=`13/280.`
Thus time taken by A, B, C is `280/43` days, `280/13` days, `280/27` days respectively.
Clearly, the time taken by A is least.