Note: A : B = 100 : 80 and A : C = 100 : 72 `:. B/C = (B/A xx A/C)` `= (80/100 xx 100/72)` `= 10/9 = 100/90` `= 100 : 90` :. B can give C 10 points

Note: A : B = 60 : 45 and A : C = 60 : 40. `:. B/C = (B/A xx A/C)` `= (45/60 xx 60/40)` `= 45/40 = 90/80` `= 90 : 80` :. B can give C 10 points in a game of 90.

Note: 1995 being on ordinary year, it has I odd day. So the first day will be one day beyond Sunday, i,e it will be Monday.

Note: 1994 being an ordinary year, it has I odd day. So, the day on 8th Feb, 1995 is one day beyond the day on 8th Feb, 1994. :. 8th Feb, 1995 was Wednesday. :. 8th Feb, 1994 was Tuesday.

Note: 1992 being a leap year, it has 2 odd days. So the day on may, 1993 is 2 days beyond the day on May 6, 1992. But, on May 6, 1993 it was Thursday. So, on May 6, 1992 it was Tuesday.

Note: Counting the number of days after 3rd November, 1994 we have Nov. Dec. Jan. Feb. March 27 + 31 + 31 + 28 + 20 = 137 days = 19 weeks + 4 days :. November of odd days = 4 :. The day on 3rd November, 1994 is (7 - 4) days beyond the day on 20th March, 1995. So, the required day is Thursday.

Note: Each day of the week is repeated after 7 days :. After 63 days, it will be Tuesday. :. After 62 days, it will be Monday.

Note: This begin a leap year, none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Wednesday. :. The day after 3 years will be Saturday.

Note: Starting with 1996, we go on counting the number of odd days till the sum is divisible by 7. Year 1996 1997 1998 1999 2000 odd days 2 1 1 1 2 = 7 odd days i,e o odd day. :. Calendar for 2001 will be the same as that of 1995.

Note: Jan Feb March 30 + 28 + 15 = 73 days