1. Question: If the price of sugar rises from Rs `6` per kg to Rs `7. 50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumption of sugar by :

    A
    `15%`

    B
    `20%`

    C
    `25%`

    D
    `30%`

    Note: Let original consumption `= 100 kg &` new consumption `= x kg` `:. 100 xx 6 = x xx 7.50 => x = 80 kg.` :. Reduction in consumption`= 20%`
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  2. Question: The price of sugar increase by `32%`. A family reduces its consumption so that the expenditure of the sugar is up by `10%` only. If the total consumption of sugar before rise was `10` kg per month, then the consumption of sugar per month at present (in kg) is :

    A
    `8 1/3`

    B
    `8 1/2`

    C
    `8 3/4`

    D
    `9`

    Note: Let original rate `= Rs. x∕kg.` Consumption `= 10 kg.` Expenditure`= Rs. 10x.` New expenditure `= 110% of Rs. 10x = 11x.` New rate`= 132% of x = (33x)/25.` New consumption `= (Expenditure/Rate)` `= (11x xx 25/(33x)` `= (25)/(3) kg.` `= 8 1/3 kg.`
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  3. Question: Prices register an increase of `10%` on food grains and `15%` on other items of expenditure. If the ratio of an employee's expenditure on food grains and other items be `2 : 5`, by how much should his salary be increased in order that he may maintain the same level of consumption as before, his present salary being `Rs. 2590 ?`

    A
    `Rs. 323.75`

    B
    `Rs. 350`

    C
    `Rs. 360.50`

    D
    None

    Note: Let expenditure on food grains and other items be Rs. 2x and Rs. 5x. `2x + 5x = 2590` `or x = 370.` `:. F = 2 xx 370` `= 740, 0 = 5 xx 370` `= 1850.` New expenditure `= 110% of 740 + 115% of 1850.` `= (110/100 xx 740 + 115/100 xx 1850)` `= Rs. (814 + 2127.50)` `= Rs. 2941.50.`
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  4. Question: The population of a town increases by `15%` annually. If its population was `8000` in `1995`, what will it be in `1997` ?

    A
    `9200`

    B
    `10400`

    C
    `9600`

    D
    `10580`

    Note: Population in `1997 = 8000 xx (1 + (15)/(100))^2` `= (8000 xx (23)/(20) xx (23)/(20))` `= 10580`.
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  5. Question: The population of a town is `18000`. It increases by `10%` during first year and by `20%` during the second year. The population after `2` years will be :

    A
    `19800`

    B
    `21600`

    C
    `23760`

    D
    None

    Note: Required population `= 18000 xx (1 + (10)/(100)) xx (1 + (20)/(100))` `= (18000 xx (11)/(10) xx 6/5)` `= 23760`.
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  6. Question: The value of a sewing machine depreciates every year by `4%`. Its value at present is `Rs 200`. What will be its value after `2` years ?

    A
    `Rs. (200 xx (23)/5)`

    B
    `Rs. [(200 xx (24)/(25))^2]`

    C
    `Rs. [200 xx ((25)/(26))^2]`

    D
    `Rs. [(200 xx (26)/(25))^2]`

    Note: value after `2` years `= Rs. [200 xx (1 - 4/(100))^2]` `= Rs. [200 xx ((24)/(25))^2]`
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  7. Question: The population of a city increases at the rate of `5%` annually. Its present population is `1,85,220`. Its population `3` years ago was :

    A
    `181500`

    B
    `183433`

    C
    `160000`

    D
    `127783`

    Note: Population `3` years ago `= (185220)/(1 + (5/(100))^3` `= (185220 xx (20)/(21) xx (20)/(21) xx (20)/(21))` `=160000`.
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  8. Question: The value of a machine depreciates at the rate of `10%` every year. It was purchased `3` years ago. If its present value is `Rs. 8748`, its purchase price was :

    A
    `Rs. 10000`

    B
    `Rs. 11372.40`

    C
    `Rs. 12000`

    D
    None

    Note: `P xx (1 - (10)/(100))^3 = 8748` `=> P = (8748 xx (10)/9 xx (10)/9 xx (10)/9)` `= Rs. 12000`.
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  9. Question: A ball pen factory decided to reduce its production by `10%` over that of previous month for next `3` months starting from February `1994`. In January `1994`, it produced `3000` ball pens. How many ball pens were produced in March `1994` ?

    A
    `2700`

    B
    `2430`

    C
    `2187`

    D
    `2400`

    Note: Required number `= 3000 xx (1 - (10)/(100))^2` `= 3000 xx 9/(10) xx 9/(10)` `= 2430`.
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  10. Question: The present population of a country estimated to be `10` crores is expected to increase to `13.31` crores during the next three years. The uniform rate of growth is :

    A
    `8%`

    B
    `12.7%`

    C
    `10%`

    D
    `15%`

    Note: `10 "crores" xx (1 + R/(100))^3` `= 13.31 "crores"`. `:. (1 + R/(100))^3` `= (13.31 "crores")/(10 "crores")` `= (13.31)/(10)` `= (1331)/(1000)` `= ((11)/(10))^3`. So, `(1 + R/(100))` `= (11)/(10)` or `= R/(100)` `=((11)/(10) - 1)` `= 1/(10)` or `R = 10`.
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