1. Question: Last year the ratio between the salaries of A and B was 3 : 4. But the ratio of their individual salaries between last year and this year were 4 : 5 and 2 : 3 respectively. If the sum of their present salaries is Rs. 4160, then how much is the salary of A now ?

    A
    Rs. 1040

    B
    Rs. 1600

    C
    Rs. 2560

    D
    Rs. 3120

    Note: Let their last years salaries be x 3x and 4x. This year,s salaries are `5/4 xx 3x `and ` 3/2 xx 4x i.e (15 x)/4 `and 6x `:. (15 x)/4 + 6x = 4160 => 39 x ` `= 16640 => 3x = 1280` :. A,s salary now` = 5/4 xx 3x = 5/4 xx 1280` `= 1600`
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  2. Question: If` x : 2 1/3 : : 21 : 50,` then the value of x is :

    A
    `(27)/(50)`

    B
    `(49)/(50)`

    C
    `1 1/(50)`

    D
    `1 1/(49)`

    Note: Not available
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  3. Question: If 8 women can grind 180 kg. of wheat in 5 days. in how many days will 28 women grind 3780 kg of wheat ?

    A
    32

    B
    45

    C
    60

    D
    30

    Note: More women, less days (indirect) More kg, more days (direct) women 28 : 8 kg 180 : 3780 :. 5 : x `:. x = ((8 xx 3780 xx 5)/(28 xx 180))` `= 30`
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  4. Question: If 40 men can build a wall 300 m. long in 12 days working 6 hours a day ; how long will 30 men take to build a similar wall 200 m long, working 8 hours a day ?

    A
    `4 1/2` days

    B
    8 days

    C
    `10 1/2` days

    D
    11 days

    Note: Less men more days (indirect) Men 30 : 40 Length 300 : 200 :. 12 : x Hrs/days 8 : 6 `:. x = ((40 xx 200 xx 6 xx 12)/(30 xx 300 8))` `= 8`
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  5. Question: In a fort ration for 2000 people was sufficient for 54 days, After 15 days more people came and the ration lasted only for 20 more days, How many people came ?

    A
    2500

    B
    2250

    C
    1900

    D
    1675

    Note: After 15 days there was ration for 2000 people for 39 days, Suppose x more came More people less days `(2000)/(2000 + x)` `= 20/39 => 78000` `= 40000 + 20x => x = 1900`
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  6. Question: One army camp had ration for 560 soldiers for 20 days, 560 soldiers reported for the camp and after 12 days, 112 soldiers were sent to another camp. For how many days, the remaining soldiers can stay in the camp without getting any new ration ?

    A
    12

    B
    16

    C
    10

    D
    None

    Note: After 12 days there was ration for 560 soldiers for 8 days. Remaining persons - (560 - 112) = 448 Less soldiers, more days `(560)/(448)` ` = x/8 => x = (560 xx 8)/(448) = 10`
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  7. Question: How many men need to be employed to complete a job in 5 days if 10 men can complete half the job in 7 days ?

    A
    7

    B
    14

    C
    28

    D
    35

    Note: 10 men can complete the job in 14 days. Less days more men `14/5 = x/10 => x = (14 xx 10)/5` `= 28`
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  8. Question: A contractor undertook to build a road in 100 days. He employed 110 men. After 45 days, he found that only `1/4` could be built. In order to complete the work in time, how many more men should be employed ?

    A
    120

    B
    160

    C
    180

    D
    270

    Note: Remaining work `= 3/4` Remaining days` = (100 - 45) = 55` Let x more men may be employed More work,more then (direct) More days, less men (indirect) Work` 1/4 : 3/4 }` Days 55 : 45 : : 110 : (110 + x) `110 + x = 3/4 xx 45 xx 110 xx 4/1 xx 1/55 = 270` `:. x = 160`
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  9. Question: 16 men complete one-fourth of a piece of work in 12 days. What is the additional number of men required to complete the work in 12 days ?

    A
    48

    B
    36

    C
    30

    D
    18

    Note: More work, more men (direct) `1/4 : 1 = 16 : 16 + x => 16/(16 + x)` `= 1/4` `:. 16 + x = 64 => x = 48`
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  10. Question: A, B and C together can do a piece of work in 20 days. After working with B and C for days, A leaves and then B and C complete the remaining work in 20 days more. In how many days, A alone could do the work ?

    A
    40

    B
    50

    C
    60

    D
    80

    Note: (b) : (A + B + C),s 8 days ' work` = (1/20 xx 8)` `= 2/5` Remaining work` = (1 - 2/5)` `= 3/5` `3/5` work is done by (b + c) in 20 days Whole work will be done by (B + C) in` (20 xx 5/3)` `= (100)/3` days :. (B + C)'s 1 days work ` = 3/100` :. A's 1 days work` = 1/20 - 3/100` `= 2/100` `= 1/50` Hence, A can finish the whole work in 50 days.
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