General Mathematics

Question: ` 0.bar8` expressed as a fraction is :
A
`8/10`

B
`88/100`

C
`88/99`

D
`8/9`

Note: `0.bar8` `= 8/9`
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Question: ` 1.bar6`expressed as a fraction is :
A
`16/10`

B
`16/9`

C
`5/3`

D
None

Note: `1.bar6 = 1 + 0.bar6` `= 1 + 6/9` `= 1 + 2/3` `= 5/3`
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Question: The value of ` 0.bar57` is :
A
` 57/10`

B
` 57/99`

C
` 26/45`

D
` 52/9`

Note: `0.bar57 = (57 - 5)/90` `= 52/90 = 26/45`.
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Question: Let F ` =0.841bar81` .when F is written as a fraction in lowest ,the denomination exceeds the numerators by :
A
` 13`

B
` 14`

C
` 29`

D
` 87`

Note: `0.841bar81` `= (84181 - 841)/99000` `= 83340/99000` `= 463/550`. Requied defferecn ` = (550 - 463)` `=87`.
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Question: ` 1,bar34` expressed as afraction is :
A
` 134/100`

B
` 134/99`

C
` 133/99`

D
` None

Note: `1.bar34` `= 1 + 0.bar34` `= 1 + (34)/99` `= (99 + 34)/99` `= 133/99`.
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Question: The value of `4.bar12`
A
` 4 (11)/(90)`

B
` 4 (11)/(99)`

C
` 371/900`

D
None

Note: `4.bar12` `= 4 + 0.bar12` `= 4(12-1)/90` `= 4(11)/90`
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Question: The vale of ` 2.1bar36` is :
A
` 47/220`

B
` 68/495`

C
` 2 (3)/(22)`

D
None

Note: `2.1bar36` `= 2 + 0.1bar36` `= 2 + (136 - 1)/990` `= 2 + 3/22` `= 2(3)/22`.
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Question: The simplification of ` ( .bar6 + .bar7 + .bar8 + .bar3)` yields the result :
A
` 2 (3)/(10)`

B
` 2 (2)/(3)`

C
` 2.bar35`

D
` 5 (3)/(10)`

Note: `0.bar6 + 0.bar7 + 0.bar8 + 0.bar3` `= (6/9 + 7/9 + 8/9 + 3/9)` `= 24/9` `= 8/3` `= 2(2/3)`.
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Question: The value of `(3.bar87 - 2.bar59)` equals :
A
` 1.20`

B
` 1.2`

C
` 1.bar27`

D
` 1.bar28`

Note: `3.bar87 - 2.bar59` `= (3 + 0.bar87) - (2 + 0.bar59)` `= (3 + 87/99) - (2 + 59/99)` `= 1+ (87/99 - 59/99)` `= 1 + 28/99` `= 1.bar28`.
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Question: ` (0.bar63 + 0.bar37)` is equal to :
A
`1`

B
`1.bar01`

C
`0.bar101`

D
`1.01`

Note: `0.bar63 + 0.bar37` `=63/99 + 37/99` `= (63 + 37)/99` `= 100/99` `= 1 (1)/99` `=1 + 0.bar01` `= 1.bar01`.
1. Report

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Question: ` 0.bar8` expressed as a fraction is :

Question: ` 1.bar6`expressed as a fraction is :

Question: The value of ` 0.bar57` is :

Question: Let F ` =0.841bar81` .when F is written as a fraction in lowest ,the denomination exceeds the numerators by :

Question: ` 1,bar34` expressed as afraction is :

Question: The value of `4.bar12`

Question: The vale of ` 2.1bar36` is :

Question: The simplification of ` ( .bar6 + .bar7 + .bar8 + .bar3)` yields the result :

Question: The value of `(3.bar87 - 2.bar59)` equals :

Question: ` (0.bar63 + 0.bar37)` is equal to :