1. Question: The difference between compound interest and the simple interest earned on a sum of money at the end of `4` years is Rs.`256.40` To find out the sum, which of the following information given in the statement P and Q is/are necessary ? p: Amount of simple interest accrued after `4` years Q: Rate of interest per annum.

    A
    Only P is necessary

    B
    only Q is necessary

    C
    Either P or Q is necessary

    D
    Neither P or Q is necessary

    E
    Both P and Q is necessary

    Note: To find out the sum we need rate, time and the difference between C.I. and S.I. So.Q is necessary.
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  2. Question: The difference between the compound interest and simple interest earned at the end of second year on a sum of money at `10%`per annum is Rs. `20`.The sum is :

    A
    `Rs.4000`

    B
    `Rs. 2000`

    C
    `Rs. 1500`

    D
    Date inadequate

    Note: Let the principal be Rs. x. Then, C.I`= [ x (1 + 10/100)^2` S.I.`= ((x xx 10 xx 2)/100)` `= x/5` :. (C.I) - (S.I) `= ((21x)/100 - x/5)` `= x/100` `:. x/100 = 20` `or x = 2000`
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  3. Question: What number should be subtracted from each of the numbers `23, 30, 57` and `78`so that the remainders may be proportional ?

    A
    `4`

    B
    `5`

    C
    `6`

    D
    `7`

    Note: Let `(23 - x)/(30 - x) = (57 - x)/(78 - x)`. `:. (23 - x)(78 - x) = (57 - x)(30 - x)` or `- 101x + 1794 = 1710 - 87x` `iff 14x = 84` `iff x = 6`.
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  4. Question: Which of the following ratios is the greatest ?

    A
    `7 : 15`

    B
    `15 : 23`

    C
    `17 : 25`

    D
    `21 : 29`

    Note: `7/(15) = 0.466`, `(15)/(23) = 0.652`, `(17)/(25) = 0.68` & `(21)/(29) = 0.724`. Clearly, `0.724`is greatest and hence `21 : 29` is greatest.
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  5. Question: A sum of Rs.`12000` deposited at compound interest becomes double after `5` years. After `20` years it will become :

    A
    `Rs. 120000`

    B
    `Rs. 192000`

    C
    `Rs. 124000`

    D
    `Rs. 96000`

    Note: `12000 xx (1 + R/100)^5` `= 24000 ⇒(1 + R/100)^5 = 2` `:. [(1 + R/100)^5]^4` `= 2^4 = 16` `or (1 + R/100)^20 = 16` `or P(1 + R/100)^20 = 16p` `or 12000(1 + R/100)^20` `= 16 xx 12000` `= 192000`.
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  6. Question: Two whole numbers whose sum is `72` cannot be in the ratio :

    A
    `5 : 7`

    B
    `3 : 5`

    C
    `4 : 5`

    D
    `3 : 4`

    Note: The sum of the ratio terms must divide `72` So, the ratio cannot be `3 : 4`.
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  7. Question: If a carton containing a dozen mirrors is dropped, which of the following cannot be the ratio of broken mirrors to unbroken mirrors ?

    A
    `2 : 1`

    B
    `3 : 1`

    C
    `3 : 2`

    D
    `7 : 5`

    Note: For dividing `12` into two whole numbers, the sum of the terms of the ratio must be a factor of `12`. So, they cannot be in the ratio `3 : 2`.
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  8. Question: The ratio of two numbers is `3 : 4` and their sum is `420`. The greater of the two numbers is :

    A
    `175`

    B
    `200`

    C
    `240`

    D
    `315`

    Note: Required number `= (420 xx 4/7)` `= 240`.
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  9. Question: The ratio between two numbers is `3 : 4` and their `1`c.m is `180`. The first number is :

    A
    `60`

    B
    `45`

    C
    `20`

    D
    `15`

    Note: Let the numbers be `3x`and `4x`. Then, their `1`c.m `= 12x`. Now, `12x = 180` `iff x = 15`. `:.`First number `= 45`.
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  10. Question: The L.C.M. and H.C.F. of two numbers `x` and `y` are `l` and `h` repectively. Then,

    A
    `l : h = x : y`

    B
    `x : h = l : y`

    C
    `x : l = y : h`

    D
    `x : h = y : l`

    Note: Product of numbers = Product of their H.C.F. & L.C.M. `:. xy = lh` `iff x/h = l/y` `iff x : h = l : y`.
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