1. Question: A reduction of `12.5%` in the price of a dining table brought down its price to Rs.`4375`. The total original price (in Rs.) of the table was :

    A
    `6000`

    B
    `5400`

    C
    `5200`

    D
    `5000`

    Note: `87.5% of x` `= 4375 ⇒ 87.5/(100) x` `= 4375.` `:. x = ((4375 xx 100)/(87.5))` `= 5000.`
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  2. Question: Of the total amount received by kiran, `205` was spent on purchases and `5%` of the remaining on transportation. If he is left with Rs. `1520`, the initial amount was :

    A
    `Rs. 2800`

    B
    `Rs. 2000`

    C
    `Rs. 2400`

    D
    `Rs. 1600`

    Note: Purchases `= 20% of x = x/5.`Balance `= x - x/5` `= (4x)/5` Transportation `= 5% of (4x)/5` `= 5/100 xx (4x)/5` `= x/25.` Balance`= (4x)5 - x/25` `= (19x)/25.` `:. (19x)/25 ` `= 1520 ⇒ x` `= (1520 xx 25)/19` `= 2000.`
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  3. Question: In a library, `20%` books are in Hindi,` 50%` of the remaining are in English and the remaining `9000` are in various other languages. What is the total number of books in English ?

    A
    `4000`

    B
    `3000`

    C
    `2250`

    D
    None of these

    Note: Hindi Books `= 20% of x = 20/(100) x = x/5` Remaining `= (x - x/5)` `= (4x)/5` English Books `= 50% of (4x)/5` `= 50/100 xx (4x)/5` `= (2x)/5` Remaining `= ((4x)/5 - (2x)/(5))` `= (2x)/5` `:. (2x)/5 = 9000 or x` `= (9000 xx 5)/2` `= 22500`
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  4. Question: A vinash spends `30%` of his income on scooter petrol,`1/4` of the remaining on house rent and the balance on food. If he spends Rs.` 300` on petrol, then what is the expenditure on house rent ?

    A
    `Rs. 525`

    B
    `Rs. 1000`

    C
    `Rs. 675`

    D
    `Rs. 175`

    Note: Spent on scooter petrol `= 30/(100) x` `= (3x)/10` Remaining `= (x - 3x/10)` `= (7x)/10` House Rent `= 1/4 xx (7x)/10` `= (7x)/40` Now, `(3x)/10 = 300 ⇒ x` `= (300 xx 10)/3` `= 1000` House Rent `= (7 xx 1000)/40` `= 175.`
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  5. Question: A man spends `35%` of his income rent,` 755` of the remaining on other items. What percentage of income does he save ?

    A
    `16.25`

    B
    `34.50`

    C
    `48.75`

    D
    None

    Note: House rent `35/(100) x` `= (7x)/20` Remaining `= (x - (7x)/(20))` `= (13x)/20` Other expenditures `= ((75)/(100) xx (13x)/(20))` `= (39x)/(80)` Saving percent `= ((13x)/(80) xx 1/x xx 100)` `= 65/4%`` `= 16.25%`
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  6. Question: The price of jute has been reduced by `20%`. If the reduced price is Rs.` 800` per quintal, the original price per quintal was

    A
    `Rs. 900`

    B
    `Rs. 640`

    C
    `Rs. 960`

    D
    `Rs. 1000`

    Note: `80% of x` `= 800 ⇒ 80/(100) x` `= 800 ⇒ x` `= 800 xx 100/80` `= 1000`
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  7. Question: Swati spends `40%` of her salary on food, `25%` on house rent `15%` on entertainment and `5%` on conveyance. If her saving at the end of a months is Rs. `1200,` then her salary per month (in Rs.) is :

    A
    `4000`

    B
    `6000`

    C
    `8000`

    D
    `10000`

    Note: Saving `= [100 - (40 + 25 + 15 + 5)]%` `= 15%` `:. 15% of x` `= 1200 ⇒ 15/(100) x` `= 1200 ⇒ x` `= (1200 xx 100/15)` `= 8000`
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  8. Question: Samir spends `40%` of his salary on food articles and one third of the remaining on transport. If he saves Rs. `450` per month which is half of the balance after spending on food items and transport, what is his monthly salary ?

    A
    `Rs. 4500`

    B
    `Rs. 2250`

    C
    `Rs. 1125`

    D
    `Rs. 2500`

    Note: Money spent on food artiles `= 40% 0f x` `= 40/(100) x` `= (2x)/5` Balance `= (x - (2x)/(5))` `= (3x)/5` Money spent on transport `= 1/3 xx (3x)/5` `= x/5` Balance now `= ((3x)/5 - x/(5))` `(2x)/5` `:. 1/2 xx (2x)/5` `= 450 ⇒ x` `= (450 xx 5)` `= 2250`
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  9. Question: If `11.25`m of a uniform iron rod weighs `42.75`kg , what will be the weight of `6` m of the same rod ?

    A
    `22.8`kg

    B
    `25.6`kg

    C
    `28`kg

    D
    `26.5`kg

    Note: Less length, less weight (Direct) `:. 11.25 : 6 :: 42.75 : x` or `x = ((6 xx 42.75)/(11.25))` `= 22.8`. `:.` Weight of `6` m long rod `= 22.8` kg.
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  10. Question: On a scale of a map, `0.6`cm represents `6.6`kg. If the distance between two points on the map is `80.5`cm, the actual distance between these points is :

    A
    `9`kg

    B
    `72.5`kg

    C
    `190.75`kg

    D
    `885.5`kg

    Note: More distance on the map, more actual distance (Direct) `0.6 : 80.5 :: 6.6 : x` or `0.6x = 80.5 xx 6.6` or `x = ((80.5 xx 6.6)/(0.6))` `= 885.5` kg. Hence, actual distance `= 885.5` km.
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