Question:Find the square root of 1471369 

`:.  sqrt(1471369)` = 1213

Question:Evaluate: `sqrt(175.2976)` 

`:. sqrt(175.2976)` = 13.24

Question:Evaluate `sqrt(0.9)` upto places of decimal. 

`:. sqrt(0.9)` = 0.948

Question:Evaluate:
(i) `sqrt 48 xx sqrt 12` 
(ii) `sqrt 128/sqrt 162` 

(i) `sqrt 48 xx sqrt 12`

= `sqrt(48 xx 12)`

= `sqrt (2 xx 2 xx 12 xx 12)`

= `(2 xx 12)`

=24

(ii) `sqrt 128/sqrt 162`

= `sqrt(128/162)`

= `sqrt (64/81)`

=`8/9`

Question:If `sqrt (14)` = 3.7416, find the value of of `sqrt (2/7)` 

`sqrt (2/7)` 

=`sqrt ((2 xx 7)/(7 xx 7))`

=`sqrt ((14)/(7 xx 7))`

=`sqrt 14 /7`

=`3.7416/7`

=0.5345

Question:If `sqrt 15` = 3.8727, find the value of `((sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)))` 

=`((sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)))`

=`((sqrt(5) + sqrt(3)))/((sqrt(5) - sqrt(3))) x ((sqrt(5) + sqrt(3)))/((sqrt(5) + sqrt(3)))`

=`((sqrt(5) + sqrt(3))^2)/(5-3)`

=`(5 + 3 +2 sqrt(5) xx sqrt(3))/2`

=`(8 + 2sqrt(15))/2`

=`(4 + sqrt(15))`

=(4 + 3.8729)

=7.8729

Question:Evaluate: `sqrt ((.036 xx .025 xx .49)/(.81 xx .016 xx .064))` 

The sum decimal places in the numerator and the denominator of the redicand being the same, we may remove the decimal places
`:.` Given Expression = `sqrt ((36 xx 25 xx 49)/(81 xx 16 xx 64))`

=`((6 xx 5 xx 7)/(9 xx 4 xx 8))`

=`35/48`

Question:Find the cube root of 2744. 

Resolving 2744 as the product of prime factors, we get:
2744 = `2^3` x `7^3`. 
`:.` `2744^((1/3))` = (2 x 7)
=14