Question: The area of a circle inscircle in an equilateral triangle of side 24 cm, is :
A
B
C
D
`18 π cm^2`
B
`24 π cm^2`
C
`36 π cm^2`
D
`48 π cm^2`
Note: `1/2 xx 24 xx h = sqrt(3)/4 xx 24 xx 24 or h`
`= 12sqrt(3)`
`:. 3r = 12sqrt(3) or r = 4sqrt(3)`
:. Area of circle` = π xx (4sqrt(3))^2`
`= (48 π) cm^2`.