Question: A cricketer has a certain average for `9` innings. In the tenth inning, he scores `100` runs ,thereby increasing his average by `8` runs. His new average is :
A
B
C
D
`20 runs`
B
`24 runs`
C
`28 runs`
D
`32 runs`
Note: Let average for `9` innings be x. Then,
`(9x + 100)/10`
`= x + 8 ⇒ 10x + 80`
`= 9x + 100 ⇒ x = 20`.
:. New average
`= (x + 8)`
`= 28 runs`.