Question: The value of` (2^(1/2) . 3^(1/3) . 4^(1/4))/(10^(-1/5) . 5^(3/5)) -: 3^(4/3 . 5^(-7/5))/(4^(-3/5) . 6)` is :
A
5
B
6
C
10
D
15
Note: Given Exp.` (2^(1/2) xx 3^(1/3) xx (2^2)^(1/4))/(2^(-1/5) xx 5^(-1/5) xx 5^(3/5)) -:
(3^(4/3) xx 5^(-7/5))/((2^2)^(-3/5) xx 2 xx 3)`
`= (2^(1/2) xx 3^(1/3) xx 2^(1/2))/(2^(-1/5) xx 5^(-1/5) xx 5^(3/5) xx (2^(-6/5) xx 2 xx 3)/(3^(4/3) xx 5^(-7/5))`
`= (2^((1/2 + 1/2 - 5/6 + 1/5 + 1)) xx 3^((1/3 + 1 - 4/3)))/(5^(- 1/5 + 3/5 - 7/5))`
`= (2 xx 3^0)/(5^(-1)`
`= 2 xx 1 xx 5 = 10`
Question: Three persons begin to walk around a circular track. They complete their revolutions in `15 1/6` seconds, ` 16 1/4` seconds and `18 2/3` seconds respectively. After what time will they be together at the starting point again ?
A
`303 1/3` sec
B
`364` sec
C
`3604` sec
D
`3640` sec
Note: Required time = L.C. M. of `91/6, 65/4` and` 56/3`
`= (L.C.M. of 91, 65, 56,)/(H.C.F. of 6, 4, 3,)`
`= (3640)/1`
`= 3640` sec.
Question: `1/4` th of Nikhil,s money is equal to `1/6` th of yogesh,s money. If both together have Rs. 600. What is the difference between their amounts ?
A
240
B
360
C
50
D
120
Note: `1/4 N = 1/6 Y => N = 4/6 Y = 3/3 Y`
Now, `N + Y = 600 => 2/3 Y + Y = 600 => Y 360`
`:. N `= (600 - 360) = 240`
Hence, (Y - N) = (360 - 240) = 120.