1. Question: The cost of carpeting a room 18 m long with a carpet 75 cm wide at 45 paise per metre is Rs. 81. The breadth of the room is :

    A
    7 m

    B
    7.5 m

    C
    8 m

    D
    8.5 m

    Note: Length of the carpet` = (Total Cost/Rate/m)` ` = (8100/450) m` ` = 180 m` Area of the room` = (180 xx 75/100) m^2` ` = 135 m^2` :. Area of the room` = Area of the carpet = 135 m^2` :. Breadth of the room` = (Area/Length)` ` = (135/18) m^2` ` = 7.5 m.`
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  2. Question: A rectangular lawn 55 m by 35 m has two roads each 4 m wide running in the middle of it, one parallel to length and the other parallel to breadth. The cost of gravelling the roads at 75 paise per sq. metre is :

    A
    `Rs. 270`

    B
    `Rs. 262.50`

    C
    `Rs. 258`

    D
    `Rs. 254.50`

    Note: Area of cross roads` = (55 xx 4 + 35 xx 4 - 4 xx 4) m^2` `= 344 m^2` :. cost of gravelling`= Rs. (344 xx 75/100)` `= Rs. 258`
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  3. Question: A rectangular field has dimensions 25 m by 15 m. Two mutually perpendicular passages, 2 m wide have been left in the central part. In rest of the fields, grass has bee grown. The area under the grass is :

    A
    `295 m^2`

    B
    `299 m^2`

    C
    `300 m^2`

    D
    `375 m^2`

    Note: Area of cross roads` = (25 xx 2 + 15 xx 2 - 2 xx 2) m^2` `= 76 m^2` Area of the field` = (25 xx 15) m^2` `= 375 m^2` Area under grass` = (375 - 76) m^2` `= 299 m^2`
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  4. Question: The ratio between the length and breadth of a rectangular field is 5 : 4. If the breadth is 20 m less than the length, the perimeter of the field is :

    A
    `260 m`

    B
    `280 m`

    C
    `360 m`

    D
    None

    Note: Let length = 5x and breadth = 4x in mertres. Then, `5x - 4x = 20 => x = 20` :. Length` = 100 m & Breadth = 80 m.` :. Perimeter` = 2 (100 + 80) m = 360 m.`
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  5. Question: The length and breadth of a rectangular piece of land are in the ratio of 5 : 4 : 3. The owner spent Rs. 3000 for surrounding it from all the sides at Rs. 7.50 per metre. The difference between its length and breadth is :

    A
    `50 m`

    B
    `100 m`

    C
    `150 m`

    D
    `200 m`

    Note: Let length = 5x and breadth = 3x in metres. Then, perimeter `= 2 (5x + 3x)` metres = 16x metres. But, perimeter `= Total cost/Rate/m` ` = (3000 xx 2/15) m` `= 400 m.` `:. 16x = 400 or x = 25.` :. Diff. in length & breadth `= (5x - 3x) = 2x = 50 m.`
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  6. Question: In what ratio must rice at Rs. 9.30 per kg be mixed with rice at Rs. 10.80 per kg so that the mixture be worth Rs. 10 per kg?

    A
    7 : 8

    B
    8 : 7

    C
    31 : 36

    D
    36 : 31

    Note: Not available
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  7. Question: The length of a plot is four times its breadth. A play ground measuring 1200 sq.m. occupies one-third of the total area of the plot. What is the length of the plot ?

    A
    `20 m`

    B
    `30 m`

    C
    `60 m`

    D
    None

    Note: Not available
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  8. Question: In what ratio must wheat at Rs. 3.20 per kg be mixed with wheat at Rs. 2.90 per kg so that the mixture be worth Rs. 3.08 per kg?

    A
    4 : 3

    B
    3 3 : 4 3 : 4 3 : 4

    C
    2 : 3

    D
    3 : 2

    Note: Not available
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  9. Question: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg ?

    A
    54 kg

    B
    63 kg

    C
    36 kg

    D
    42 kg

    Note: Not available
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  10. Question: The length of a rectangle is twice its breadth and one of its diagonals measure `10sqrt(5)` cm. The perimeter of the rectangle is :

    A
    `60 cm`

    B
    `50 cm`

    C
    `250 cm`

    D
    None

    Note: Let breadth = x cm and length = 2x cm. Then, `x^2 + (2x)^2` `= (10sqrt(5)^2 or 5x^2` `= 500 or x^2` `= 100 or x = 10` :. perimeter` = 2 (2x + x) cm` `= 6x cm = 60 cm.`
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