Question:Requred digit
Answer
=unit digit in the product `(4 xx 8 xx 7 xx 3)`=2
Question:Requred digit
=unit digit in the product `(4 xx 8 xx 7 xx 3)`=2
Question:`9 xx 6 xx 4`216.
In order to obtain 2 at the unit place it must be multiplied by a number whose unit digit is 7. So,*must be replace by 7.
Question:Unit digit in `7^4`is 1.`
:.Unit digit in `7^68`is 1. :.Unit digit in `7^71`is 3. `[1 xx 7 xx 7 xx 7` gives unit digit 3] Again,every power of 6 will give unit digit 6. :. Unit digit in `6^59` is 6. Clearly,unit digit in `3^4` is 1. So,unit digit in `3^64` is 1 :.Unit digit in `3^65` is 3. :. Unit digit in `(7^71 xx 6^59 xx 3^65)` is 4. `[3 xx 6 xx 3`gives unit digit 4]`
Question:Unit digit in the given product=unit digit in `7^153 xx 1^72`.
Now `7^4`gives unit digit 1. :.`7^152` gives unit digit 1. :.`7^152` gives unit digit `(1 xx 7)=7` Also `1^72`gives digit 1. :.Unit digit in the product =`(7 xx 1)=7`.
Question:Unit digit in `7^4` is 1`
So,unit digit in `7^92` is 1. :.Unit digit in `7^95` is 3. [:. Unit digit in `1 xx 7 xx 7 xx `is 3 ] Unit digit in `3^4`is 1 :. Unit digit in `3^56` is 1. :. Unit digit in `3^58` is 9. [:.Unit digit in `1 xx 3 xx 3 xx` is 9] :. Unit digit in `(7^95 - 3^58)` is 4.[Subtracting unit digit 9 from unit digit]
Question:`4^11 xx 7^5 xx 11^2`
=`(2 xx 2)^11 xx 7^5 xx 11^2` =`2^11 xx 2^11 xx 7^5 xx 11^2` =`2^22 xx 7^5 xx 11^2`. :.The number of prime factors is (22 + 5 + 2)=29