Question:যদি হয়, a + b + c = 0 তবে দেখাও যে, ক.` a^3 + b^3 + c^3 = 3abc` খ.`(b + c)^2/(3ab) + (c + a)^2/(3ca) + (a + b)^2/(3ab) = 1` 

Answer ক. দেওয়া আছে, a + b + c = 0 বা, a + b = c বা, `(a + b)^3 = (-c)^3` [উভয়পক্ষকে ঘন করে] বা, `a^3 + b^3 + 3ab(a + b) = -c^3` বা, `a^3 + b^3 + 3ab(-c) = -c^3` [:. a + b = - c] `:. a^3 + b^3 + c^3 = 3abc` (দেখানো হলো) খ. দেওয়া আছে, a + b + c = 0 :. a + b = -c, b + c = - a c + a = -b বামপক্ষ `= (b + c)^2/(3bc) + (c + a)^2/(3ca) + (a + b)^2/(3ab)` `= (-a)^2/(3bc) + (-b)^2/(3ca) + (-c)^2/(3ab)` `= a^2/(3bc) + b^2/(3ca) + c^2/(3ab)` `= (a^3 + b^3 + c^3)/(3abc)` `= ((a + b)^3 - 3ab(a + b) + c^3)/(3abc)` [সূত্র ব্যবহার করে] `= ((-c)^3 - 3ab(-c) + c^3)/(3abc)` [:. a + b = - c] `= (-c^3 + 3abc + c^3)/(3abc)` `= (3abc)/(3abc)` `= 1` = ডানপক্ষ `:. (b + c)^2/(3bc) + (c + a)^2/(3ca) + (a + b)^2/(3ab) ` `= 1` (দেখানো হলো) 

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jodi hoyo, a + b + c = 0 tobe dekhao je, ka.` a^3 + b^3 + c^3 = 3abc` kh.`(b + c)^2/(3ab) + (c + a)^2/(3ca) + (a + b)^2/(3ab) = 1`
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