Question:যদি হয়, a + b + c = 0 তবে দেখাও যে,
ক.` a^3 + b^3 + c^3 = 3abc`
খ.`(b + c)^2/(3ab) + (c + a)^2/(3ca) + (a + b)^2/(3ab) = 1`
Answer ক. দেওয়া আছে, a + b + c = 0
বা, a + b = c
বা, `(a + b)^3 = (-c)^3` [উভয়পক্ষকে ঘন করে]
বা, `a^3 + b^3 + 3ab(a + b) = -c^3`
বা, `a^3 + b^3 + 3ab(-c) = -c^3` [:. a + b = - c]
`:. a^3 + b^3 + c^3 = 3abc` (দেখানো হলো)
খ. দেওয়া আছে,
a + b + c = 0
:. a + b = -c, b + c = - a
c + a = -b
বামপক্ষ `= (b + c)^2/(3bc) + (c + a)^2/(3ca) + (a + b)^2/(3ab)`
`= (-a)^2/(3bc) + (-b)^2/(3ca) + (-c)^2/(3ab)`
`= a^2/(3bc) + b^2/(3ca) + c^2/(3ab)`
`= (a^3 + b^3 + c^3)/(3abc)`
`= ((a + b)^3 - 3ab(a + b) + c^3)/(3abc)` [সূত্র ব্যবহার করে]
`= ((-c)^3 - 3ab(-c) + c^3)/(3abc)` [:. a + b = - c]
`= (-c^3 + 3abc + c^3)/(3abc)`
`= (3abc)/(3abc)`
`= 1`
= ডানপক্ষ
`:. (b + c)^2/(3bc) + (c + a)^2/(3ca) + (a + b)^2/(3ab) `
`= 1` (দেখানো হলো)