দেখাও যে x 1 2 3x 4 3x2 2x 8, বীজগণিতিক রাশি, গণিত

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Question:দেখাও যে,
  ` (x + 1) (x + 2) (3x - 1) (3x - 4) = (3x^2 + 2x - 1) (3x^2 + 2x - 8)`

Answer বামপক্ষ,  
 `= (x + 1) (x + 2) (3x - 1) (3x - 4)`

 `= (x + 1) (3x - 1) (x + 2) (3x - 4)`

 `= (3x^2 + 3x - x - 1) (3x^2 + 6x - 4x - 8)`

 `= (3x^2 + 2x - 1) (3x^2 + 2x - 8)`

    = ডানপক্ষ

   `:. (x + 1) (x + 2) (3x - 1) (3x - 4) = (3x^2 + 2x - 1) (3x^2 + 2x - 8)` (দেখানো হলো)

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dekhao je, ` (x + 1) (x + 2) (3x - 1) (3x - 4) = (3x^2 + 2x - 1) (3x^2 + 2x - 8)`

Question:দেখাও যে, ` (x + 1) (x + 2) (3x - 1) (3x - 4) = (3x^2 + 2x - 1) (3x^2 + 2x - 8)`