1. Question: The L.C.M. of 26,56,104 and 182 is :

    A
    546

    B
    1274

    C
    728

    D
    784

    Note: solution: 13 | 26 - 56 - 104 - 182 ___|__________________________ 7 | 2 -56 - 8 - 14 ___|___________________________ 2 | 2 - 8 - 8 - 2 ___|___________________________ 4 | 1 - 4 - 4 - 1 ___|___________________________ | 1 - 1 - 1 - 1 `:.`L.C.M.=(13`xx`7`xx`2`xx`4`xx`)=728.
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  2. Question: The L.C.M. of 148 and 185 is :

    A
    680

    B
    740

    C
    3700

    D
    2960

    Note: solution: H.C.F. of 148 and 185 is 37. L.C.M.=`((148xx185)/37)` =740.
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  3. Question: The L.C.M. of `2^3``xx``3^2``xx`5`xx`11, `2^4``xx``3^4``xx``5^2``xx`7 and `2^5``xx``3^3``xx``5^3``xx``7^2``xx`11 is:

    A
    `2^5``xx``3^4``xx``5^3`

    B
    `2^5``xx``3^4``xx``5^3``xx``7^3``xx`11

    C
    `2^3``xx``3^2``xx`5`xx`7`xx`11

    D
    `2^3``xx``3^2``xx`5

    Note: solution: L.C.M. =product of highest powers of prime factors =`2^5``xx``3^4``xx``5^3``xx``7^2``xx`11.
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  4. Question: The L.C.M. of `1/3`,`5/6`,`2/9`,`4/27` is:

    A
    `1/54`

    B
    `10/27`

    C
    `20/3`

    D
    None of these

    Note: solution: L.C.M.=`(L.C.M. of 1,5,2,4)/(H.C.F. of 3,6,9,27)` =`20/3`.
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  5. Question: The L.C.M. of `2/3`,`3/5`,`4/7``9/131` is:

    A
    36

    B
    `1/36`

    C
    `1/1365`

    D
    `12/455`

    Note: solution: L.C.M.=`(L.C.M. of 2,3,4,9)/(H.C.F. of 3,5,7,13)`= `36/1`=36.
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  6. Question: Two numbers are in the ratio of 15 : 11. If their H.C.F. is 13, then the numbers are :

    A
    12,55

    B
    105, 77

    C
    15, 11

    D
    195,143

    Note: solution: Let the required numbers be 15x and 11x. Then ,their H.C.F. is x. so, x=13. `:.`The numbers are 15 `xx` 13 & 11 `xx` 13 i.e. 195 & 143.
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  7. Question: Three numbers are in the ratio 1:2:3 and their H.C.F. is 12. The numbers are:

    A
    12,24,36

    B
    10,20,30

    C
    5,10,15

    D
    4,8,12

    Note: solution: Let the required numbers be x, 2x and 3x. Then, their H.C.F. =x. So, x=12. `:.` The number are 12,24 and 36.
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  8. Question: The sum of two numbers is 216 and their H.C.F. is 27. The numbers are:

    A
    27,189

    B
    154,162

    C
    108,108

    D
    81,189

    Note: solution: Let the required numbers be`27a and 27b`. Then, `27a+27b=216` `=> a+b=8`. Now,co-primes with sum 8 are `(1,7) & (3,5)`. `:.` Required number are `(27 xx 1, 27 xx 7) & (27 xx 3, 27 xx 5)` i.e. `(27,189) & (81,135)`. Out of these, the given one in the answer is the pair `(27,189)`.
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  9. Question: The sum of two numbers is 528 and their H.C.F. is 33. The number of pairs of such numbers satisfying the above condition is:

    A
    6

    B
    12

    C
    8

    D
    4

    Note: solution: Let the required numbers be `33a and 33b`. Then, `33a +33b=528` or `a+b=16.` Now, two co-primes with sum 16 are: `(1,15),(3,13),(5,11) & (7,9)` `:.` Numbers with sum 528 and H.C.F. 33 are: `(33 xx 1, 33 xx 15),(33 xx 3, 33 xx 13),(33 xx 5, 33 xx 11),(33 xx 7, 33 xx 9)`. The number of such pairs is 4.
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  10. Question: The product of two 2-digit numbers is 2028 and their G.C.M. is 13. The numbers are:

    A
    26,78

    B
    39,52

    C
    13,156

    D
    36,68

    Note: solution: Let the numbers be 13a and 13b.Then, `13a xx 13b=2028` `=> ab=12`. Now, co-primes with product 12 are (1,12) and (3,4). So, the numbers with H.C.F. 13 and product 2028 are: `(13 xx 1, 13 xx 12) and (13 xx 3, 13 xx 4)`. `:.` Required 2-digit numbers are 39 & 52.
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