Question: The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18, is :
A
74
B
94
C
184
D
364
Note:solution:
L.C.M. of `6, 9, 15, 18 is 90`.
Let required number be `90k + 4`, which is a multiple of 7.
Letast value of k for which `(90k + 4 )`is divisible by 7 is k=4.
`:.` Required number = `90 xx 4 + 4 = 364`.
Question: The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is :
A
1677
B
1683
C
2523
D
3363
Note:solution:
L.C.M. of `5, 6, 7, 8 = 840`.
`:.` Required number is of the from` 840k + 3`.
Least value of k for which `(840k +3)` is divisible by 9 is k = 2.
`:.` Required number = `(840 xx 2+3) = 1683`.
Question: The least number which when divided by 5, 6, 8, 9 and 12 leaves a remainder 1 in each case, but when divided by 13 leaves no remainder, is :
A
361
B
721
C
1801
D
3601
Note:solution:
L.C.M. of `5, 6, 8, 9, 12 = 360`.
`:.` Required number is of the form 360k + 1.
Least value of k for which `360k + 1` is divisible by 13 is k = 10.
`:.` Required number = `(360 xx 10 +1) = 3601`.
Question: An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is :
A
10.30 a.m.
B
10.31 a.m.
C
10.59 a.m.
D
11 a.m.
Note:solution:
L.C.M. of 60 and 62 seconds is 1860 sec = 31 min.
`:.` They will beep together at 10.31 a.m.
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 second respectively. In 30 minutes, how many times do they toll together ?
A
4
B
10
C
15
D
16
Note:solution:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds i.e. 2 minutes.
In 30 minutes, they will toll together in `(30/2)` + 1 =16 times.
Question: The traffic lights at three different road crossings change after every 48 sec, 72 sec and 108 sec respectively. If they all change simultaneously at 8 :20 :00 hours, then they will again change simultaneously at :
A
8 :27 : 12 hrs
B
8 : 27 : 24 hrs
C
8 : 27 : 36 hrs
D
8 : 27 : 48 hrs
Note:solution:
Interval of change = `(1.c.m. of 48, 72, 108) sec. = 432` sec.
`:.`The lights will change simultaneously after every 432 seconds, i.e. 7 min. 12 sec.
`:.` Next simultaneous change will take place at` 8 : 27 : 12` hrs.