Question: A train starts full of passengers and takes `280` more .At the seceond station,it drops one half of the new total anf takes `12`more .On arriving at the third station ,it is found to have `248`passengers .The number of passsengers in the begining was :
Note: Let the number of passengers in the begining be x,
After 1st station ,passengers
`= (x - x/3) + 280`
`= ((2x)/3 + 280)`
After 2nd starion ,passengers
`= ((2x)/3 +280) - 1/2 ((2x)/3 + 280) + 12`
`:. 1/2((2x)/3 + 280) + 12= 248`
`or (2x)/3 + 280`
`= 2 xx 236`
`or (2x)/3 = 192`
`:. x = (192 xx 3/2) = 288`.