Question:যদি `a=sqrt2x^2-8`এবং `b=4/x+5/x`হয় ।
   a=0 হলে x= ? 

A 4 
B `+-4` 
C 2 
D `+-2` 

+ Answer
D 

+ Explanation
ব্যাখ্যা: `sqrt2x^2-8=0`বা, `2x^2-8=0`বা, `x^2-4=0`
      :. x =`+-2`.

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Rashada Nipa

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