1. Question: A square and a rectangle have equal areas. If their perimeters are p1 and p2 respectively, than :

    A
    `p1 < p2`

    B
    `p1 = p2`

    C
    `p1 > p2`

    D
    None

    Note: Not available
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  2. Question: If the perimeters of a square and a rectangle are the same, than the areas A and B enclosed by them would satisfy the condition :

    A
    `A < B`

    B
    `A <= B`

    C
    `A > B`

    D
    `A >= B`

    Note: Let side of a square = a. length of rect. = x & breadth of rect. = y. `4a = 2 (x + y) => (x + y)/2 = a` Area of square` = a^2 = ((x + y)^2/2)` So, A`= ((x + y)^2/2)` Area of rect. = xy. So, B = xy. `(x + y)/2 > x^1/2 y^1/2` [:. A.M. > G.M.] `=> ((x + y )^2/2)`> xy i. e.A > B.
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  3. Question: The ratio of the area of a square to that of the square drawn on its diagonal is :

    A
    `1 : 1`

    B
    `1 : 2`

    C
    `1 : 3`

    D
    `1 : 4`

    Note: Let side of a square = a. Then, its diagonal` = sqrt(2) a`. Ratio of areas of squares with sides a & `sqrt(2) a` `= a^2/(sqrt(2) a)^2` `= 1/2 or 1 : 2`
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  4. Question: If the ratio of the areas of two squares is 9 : 1, the ratio of their perimeters is :

    A
    `9 : 1`

    B
    `3 : 1`

    C
    `1 : 3`

    D
    `3 : 4`

    Note: Let the sides of two squares be a and b respectively. Then, `a^2/b^2 = 9/1` or `(a/b)^2` `= (3/1)^2` or `a/b = 3/1` :. Ratio of their perimeters `= (4a)/(4b) = a/b = 3/1` or ` 3 : 1`
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  5. Question: If the diagonal of a rectangle and a square, each is equal to 80 cm and the difference of their areas is 100 sq. cm, the side of the rectangle are :

    A
    `35 cm, 15 cm`

    B
    `30 cm, 10 cm`

    C
    `28 cm, 12 cm`

    D
    ` 25 cm, 15 cm`

    Note: perimeter of square = 80 cm. So, side of square = 20 cm. Area of the square` = (20 xx 20) cm^2` `= 400 cm^2` With same perimeters, area of the square is larger. :. Area of rectangle`= (400 - 100) cm^2` `= 300 cm^2` Let length of rect. = x & its breadth = y. Then, xy = 300 and x + y = 40 `:. (x - y) = sqrt((x + y))^2- 4xy` `= sqrt(1600 - 1200) = 20` Solving `x + y = 40 & x - y = 20,` we get` x = 30, y = 10` :. Sides are` 30 cm, 10 cm.`
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  6. Question: Of the two square fields, the area of one is 1 hectare, while the other one is broader by 1%. The difference in their areas is :

    A
    `100 m^2`

    B
    `101 m^2`

    C
    `200 m^2`

    D
    `201 m^2`

    Note: Area of first square` = 10000 sq.` metres. Side of this square` = sqrt(10000) m = 201 m^2` Side of the new square` = 101 m` Difference in areas` = (101)^2 - (100)^2` ` = 201 m^2`
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  7. Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq. cm. The length of the rectangle is

    A
    `20 cm`

    B
    `30 cm`

    C
    `40 cm`

    D
    `50 cm`

    Note: Let breadth = x. Then, length = 2x `(2x - 5) (x + 5) - 2x xx x` `= 75 or x = 20`. `:. Length = 40 cm.`
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  8. Question: The cost of cultivating a square field at the rate of Rs. 135 per hectare is Rs. 1215. The cost of putting a fence around it at the rate of 75 paise per metre would be :

    A
    `Rs. 360`

    B
    `Rs. 810`

    C
    `Rs. 900`

    D
    `Rs. 1800`

    Note: Area `= (total cost)/Rate` `= (1215/135) hectares` `= (9 xx 10000) sq.m,` :. Side of the square` = sqrt(90000) = 300 m.` perimeter of the field` = (300 xx 4) m.` `= 1200 m.` cost of fencing` = Rs. (1200 xx 3/4)` `= Rs. 900`
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  9. Question: Within a rectangular garden 10 m wide and 20 m long, we wish to pave a walk around the borders of uniform so as to leave an area of `96 m^2`for flowers.How wide should the walk be ?

    A
    1 m

    B
    2 m

    C
    2.1 m

    D
    2.5 m

    Note: Let the width of walk be x metres. Then, `(20 - 2x) (10 - 2x) = 96` `or 4x^2 + 60x - 104` `= 0 or x^2 + 15x - 26 = 0` `or (x - 13) (x - 2) = 0` So, `x = 2 [:. x =/ 13]
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  10. Question: The cost of carpeting a room 18 m long with a carpet 75 cm wide at 45 paise per metre is Rs. 81. The breadth of the room is :

    A
    7 m

    B
    7.5 m

    C
    8 m

    D
    8.5 m

    Note: Length of the carpet` = (Total Cost/Rate/m)` ` = (8100/450) m` ` = 180 m` Area of the room` = (180 xx 75/100) m^2` ` = 135 m^2` :. Area of the room` = Area of the carpet = 135 m^2` :. Breadth of the room` = (Area/Length)` ` = (135/18) m^2` ` = 7.5 m.`
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