Question:১সরল কর : `(3^3. 3^5)/3^6`
Answer
সমাধান : `(3^3. 3^5)/3^6` `= 3^(3 + 5)/3^6` `= 3^8/3^6` `= 3^ (8 - 6)` `= 3^2` `= 9` (Ans.)
Question:১সরল কর : `(3^3. 3^5)/3^6`
সমাধান : `(3^3. 3^5)/3^6` `= 3^(3 + 5)/3^6` `= 3^8/3^6` `= 3^ (8 - 6)` `= 3^2` `= 9` (Ans.)
Question:২সরল কর : `(5^3 . 8)/(2^4 . 125)`
সমাধান : `(5^3 . 8)/(2^4 . 125)` `= (5^3 . 2^3)/(2^4 . 5^3)` `= 5^(3-3). 2^(3-4)` `= 5^0 . 2^-1` `= 1 . 1/2` `= 1/2` (Ans.)
Question:৩সরল কর : `(7^3 xx 7^-3)/(3 xx 3^-4)`
সমাধান : `(7^3 xx 7^-3)/(3 xx 3^-4)` `= 7^(3 - 3)/ 3^(1 - 3)` `= 7^0/3^-3` `= 1/3^-3` `= 1 xx 3^3` `= 27` (Ans.)
Question:৪সরল `(root(3)(7^2) . root(3)(7))/sqrt(7)`
সমাধান: `(root(3)(7^2) . root(3)(7))/sqrt(7)` `= ((7^2)^(1/3) . 7^(1/3))/7^(1/2)` `= 7^(2/3 + 1/3 - 1/2)` `= 7^((4 + 2 - 3)/6)` `= 7^(3/6)` `= 7^(1/2)` `= sqrt (7)` Ans.
Question:৫সরল কর `(2^-1 + 5^-1)^-1`
সমাধান `(2^-1 + 5^-1)^-1` `= (1/2 + 1/5)^-1` `= ((5 + 2)/10)^-1` `= (7/10)^-1` `= 1/7` `= 1 xx 10/7` `= 10/7` Ans.
Question:৬সরল কর ` (2a^-1 + 3b^-1)^-1`
সমাধান ` (2a^-1 + 3b^-1)^-1` `= (2 xx 1/a + 3 xx 1/b)^-1` `= (2/a + 3/b)^-1` `= ((2b + 3a)/(ab))^-1` `= 1/((2b + 3a)/(ab))` `= 1 xx (ab)/(3a + 2b)` `= (ab)/(3a + 2b)` Ans.
Question:৭ সরল কর `((a^2 b^-1)/(a^-2 b))^2`
সমাধান `((a^2 b^-1)/(a^-2 b))^2` `= (a^(2 + 2) b^(- 1 - 1))^2` `= (a^4 b^-2)^2` `= a^8 b^-4` `= a^8/b^4` Ans.
Question:৮ সরল কর `sqrt(x^-1)y . sqrt(y^-1)z . sqrt(z^-1)x`, `(x > 0, y > 0, z > 0)`
সমাধান: `sqrt(x^-1)y . sqrt(y^-1)z . sqrt(z^-1)x` `= (x^-1 y)^(1/2) (y^-1 z)^(1/2) (z^-1 x)^(1/2)` `= (x^-1 y . y^-1 z . z^-1 x)^(1/2)` `= (x^(- 1 + 1) . y^(1 - 1) . z^(1 - 1))^(1/2)` `= (x^0 . y^0 . z^0)^(1/2)` `= (1 xx 1 xx 1)^(1/2)` `= 1` Ans.বিকল্প সমাধান: `sqrt(x^-1)y . sqrt(y^-1)z . sqrt(z^-1)x` `= sqrt(1/x).y sqrt(1/y).z sqrt(1/z).x` `= sqrt(y/x) . sqrt(z/y) . sqrt(x/z)` `= sqrt(y)/sqrt(x) . sqrt(z)/sqrt(y) . sqrt(x)/sqrt(z)` `= 1` Ans.
Question:৯ সরল কর `(2^(n + 4) - 4.2^(n + 1))/2^(n + 2) -: 2`
সমাধান: `(2^(n + 4) - 4.2^(n + 1))/(2^(n + 2) -: 2)` `= (2^n xx 2^4 - 4 xx 2^n xx 2^1)/(2^(n + 2) -: 2^1)` `= (2^n xx 16 - 8 xx 2^n)/2^(n + 2 - 1)` `= (2^n (16 - 8))/2^(n + 1)` `= (2^n xx 8)/(2^n xx 2^1)` `= 8/2` `= 4` Ans.
Question:১০. সরল কর: `(3^(m + 1))/((3^m)^(m - 1)) -: (9^(m + 1))/((3^(m - 1))^(m + 1))`
সমাধান: `(3^(m + 1))/((3^m)^(m - 1)) -: (9^(m + 1))/((3^(m - 1))^(m + 1))` `= (3^(m + 1))/(3^(m^2 - m)) -: ((3^2)^(m + 1))/(3^((m - 1)(m + 1)))` `= (3^(m + 1))/(3^(m^2 - m)) -: (3^(2m + 2))/(3^(m^2 - 1)` `= 3^(m + 1 - m^2 + m) -: 3^(2m + 2 - m^2 + 1)` `= 3^(2m - m^2 + 1) -: 3^(2m - m^2 + 3)` `= 3^((2m - m^2 + 1)-(2m - m^2 + 3))` `= 3^(2m - m^2 + 1 - 2m + m^2 - 3)` `= 3^(-2)` `= 1/3^2` `= 1/9` Ans.