Question:দুইটি রাশির বর্গের অন্তররুপে প্রকাশ কর: ক.(5p - 3q) (p + 7q) খ. (6a + 9b) (7b - 8a) গ. (3x + 5y) (7x - 5y) ঘ. (5x + 13) (5x - 13)
Answer
ক. (5p - 3q) (p + 7q) আমরা জানি, ab =` ((a + b)/2)^2 - ((a - b)/2)^2` :. (5p - 3q) (p + 7q) `= {((5p - 3q) + (p + 7q))/2}^2 - {((5p - 3q) - (p + 7q))/2}^2` `= ((5p - 3q + p + 7q)/2)^2 - ((5p - 3q - p - 7q)/2)^2` `= ((6p + 4q)/2)^2 - ((4p - 10q)/2)^2` `= {(2(3p + 2q))/2}^2 - {(2(2p - 5q))/2}^2` `= (3p + 2q)^2 - (2p - 5q)^2` উত্তর: `(3p + 2q)^2 - (2p - 5q)^2` খ.(6a + 9b) (7b - 8a) আমরা জানি, ab =` ((a + b)/2)^2 - ((a - b)/2)^2` :. (6a + 9b) (7b - 8a) = `{((6a + 9b) + (7b - 8a))/2)^2 - {((6a + 9b) - (7b - 8a))/2}^2` = `((6a + 9b + 7b - 8a)/2)^2 - ((6a + 9b - 7b + 8a)/2)^2` =` ((16b - 2a)/2)^2 - ((2b + 14a)/2)^2` =` {(2(8b - a))/2}^2 - {(2(b + 7a))/2}^2` =` (8b - a)^2 - (b + 7a)^2` উত্তর: ` (8b - a)^2 - (b + 7a)^2` গ. (3x + 5y) (7x - 5y) আমরা জানি, ab =` ((a + b)/2)^2 - ((a - b)/2)^2` :. (3x + 5y) (7x - 5y) =` {((3x + 5y) + (7x - 5y))/2}^2 - {((3x + 5y) - (7x - 5y))/2}^2` =` ((3x + 5y + 7x - 5y)/2)^2 - ((3x + 5y - 7x + 5y)/2)^2` =` ((10x)/2)^2 - ((- 4x + 10y)/2)^2` =` (5x)^2 - {(- 2 (2x - 5y))/2}^2` =` (5x)^2 - (2x - 5y)^2` = `(5x)^2 - (2x - 5y)^2` উত্তর: `(5x)^2 - (2x - 5y)^2` ঘ. (5x + 13) (5x - 13) আমরা জানি, ab = `((a + b)/2)^2 - ((a - b)/2)^2` :. (5x + 13) (5x - 13) =` {((5x + 13) + (5x - 13))/2}^2 - {((5x + 13) - (5x - 13))/2}^2` =` ((5x + 13 + 5x - 13)/2)^2 - ((5x + 13 - 5x + 13)/2)^2` =` ((10x)/2)^2 - ((26)/2)^2` = `(5x)^2 - (13)^2` উত্তর: `(5x)^2 - (13)^2`