Answer`a^2 + 6a + 8 - y^2 + 2y`
`= a^2 + 4a + 2a + 8 - y^2 + 2y`
`= a(a + 4) + 2(a + 4) - y^2 + 2y`
`= (a + 4) (a + 2) + 2y - y^2`
ধরি, a + b = p
a + 2 = q
------------
2 = p - q [বিয়োগ করে]
:. p - q = 2
এখন, `(a + 4) (a + 2) + 2y - y^2`
`= pq + (p - q) y - y^2`
[:. a + 4 = p, a + 2 = q এবং 2 = p - q]
`= pq + py - qy - y^2`
`= p(q + y) - y(q + y)`
`= (q + y) (p - y)`
`= (a + 2 + y) (a + 4 - y)` [p, q]
`= (a + y + 2) (a - y + 4)` (Ans)
বিকল্প সমাধান:
`a^2 + 6a + 8 - y^2 + 2y`
`= a^2 + 6a + 9 - y^2 + 2y - 1`
`= a^2 + 6a + 9 - (y^2 - 2y + 1)`
`= {(a)^2 + 2.a.3 + (3)^2} - {(y)^2 - 2.y.1 + (1)^2}`
`= (a + 3)^2 - (y - 1)^2`
`= (a + 3 + y - 1) (a + 3 - y + 1)`
`= (a + y + 2) (a - y + 4)` (Ans)